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单词 ENOMM0113
释义
104 convergent series
=
1
|
The proof of this test relies on making clever compari-
son to a geometric series. (If, for all terms,
n
anrfor
some value r, then anrnand a comparison can be
made.) This test is often used if the series contains
terms involving exponents. For example, consider the
series . Here the nth term of the series is
given by , and we have:
. By the root test, the series must
converge.
The Integral Test
This test applies only to series with positive terms.
Suppose the terms of a series are given
by a formula an= f(n),where the function f(x) is
continuous, positive, and decreasing for x1:
i. If the
IMPROPER INTEGRAL
1f(x)dx con-
verges, then the series converges.
ii. If the improper integral
1f(x)dx diverges,
then the series diverges.
This can be proved geometrically by drawing rectan-
gles of width 1 just above and just below the graph of
y= f(x) for x 1, and then comparing the total area
of all the rectangles with the area under the curve.
To illustrate the test, consider the series . Since
converges, we have that
the series converges. In general, one can establish
in this way the p-series test.
The p-Series Test
A series of the form with pa real
number converges if p > 1and diverges if p 1.
A series of the form is called a p-series.
Absolute Convergence Test
Suppose is a series with both positive
and negative terms. If the corresponding series
with all terms made positive converges,
then the original series also converges.
One can use any of the first six tests described above
to determine whether or not converges. The
validity of the absolute convergence test is established
in the discussion on
ABSOLUTE CONVERGENCE
.
Since we have established, for example, that
converges, the absolute
convergence test now assures us that the variant series
also
converges (as does any other variation that involves the
insertion of negative signs).
The absolute-convergence test does not cover all
cases. It is still possible that a series with negative
terms, , might converge even though
diverges. This phenomenon is called
CONDITIONAL
CONVERGENCE
.
Alternating-Series Test
If the terms of a series alternate in sign
and satisfy
i. a1 a2 a3
ii. an0
then the series converges.
(See
ALTERNATING SERIES
.) This test shows, for
example, that the alternating
HARMONIC SERIES
converges even though the
11
2
1
3
1
4
1
5
−+−+
L
an
n=
1
|
an
n=
1
an
n=
1
1
4
1
9
1
16
1
25
1
36
1
49
1
64
1
81
1
100
+−+−+−+ +L
111
4
1
9
1
16
2
1n
n=
=+ + + +L
||an
n=
1
an
n=
1
||an
n=
1
an
n=
1
1
1np
n=
1
1np
n=
1
2
1n
n=
11
011
2
11
xdx x
=−
=−−=()
1
2
1n
n=
an
n=
1
an
n=
1
an
n=
1
limnnn
→∞ +=<
101
2
limnn
na
→∞
a
nn
nn
=+
()
1
2
1
2
1nn
n
n+
()
=
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更新时间:2025/5/13 9:17:25