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单词 ENOMM0230
释义
Gaussian elimination 221
Consequences for Matrix Theory
Any system of linear equations can be represented via a
coefficient
MATRIX
and a column of constant values.
For instance, for our example:
y+ 3z= 0
2x+ 4y– 2z= 18
x+ 5y+ 3z= 14
the coefficient matrix, call it A, is given by:
the column of constant values, call it b, is:
Any elementary row operation performed on the origi-
nal set of equations corresponds to an operation on the
rows of the coefficient matrix Aand the column matrix
b. For instance, in the example above, our first opera-
tion was to interchange the first and second rows. This
can be accomplished by multiplying Aand beach by
the
PERMUTATION
matrix
We have:
Similarly, the elementary row operation of dividing the
first row through by 2 is accomplished by multiplica-
tion with the matrix
and the act of subtracting the first equation from the
first is accomplished by multiplication with the matrix:
In this way one can see that every elementary row oper-
ation corresponds to multiplication by an elementary
matrix. This observation has an important consequence.
The inverse of a square matrix Ais simply the
product of the elementary matrices that reduce
Ato the identity matrix.
Our example explains this. We used elementary row
operations to reduce the system of equations to the
equivalent system:
x= 2
y= 3
z= –1
That is, we found a collection of eight elementary
matrices E1, E2, …, E8such that application of these
eight matrices reduced the matrix of coefficients Ato
the
IDENTITY MATRIX
I.
E8E7E6E5E4E3E2E1A= I
If we let Bbe the matrix E8E7E6E5E4E3E2E1, then
we have BA = I, which means that B= A–1, the
INVERSE
MATRIX
to A. (As the
DETERMINANT
of the identity
matrix Iis 1, the equation E8E7E6E5E4E3E2E1A= I
shows that the determinant of Acannot be zero. Thus,
as the study of determinants shows, the matrix Adoes
indeed have an inverse.) Notice that the matrix Bis the
same elementary row operations applied to the matrix
I. This result provides a constructive method for com-
puting the inverse to a matrix A.
To compute the inverse of a matrix A, write the
matrix Aand the matrix Iside by side. Perform
100
010
101
1200
010
001
/
010
100
001
01 3
24 2
15 3
24 2
01 3
15 3
010
100
001
0
18
14
18
0
14
=
=
010
100
001
b=
0
18
14
A=−
01 3
24 2
15 3
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