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单词 ENOMM0498
释义
sums of powers 489
2×(1 + 2 + 3 +…+ n) = n×(n+ 1)
In a similar vein, one can show that six copies of a
three-dimensional “staircase” stack together to form an
n×(n+ 1) ×(2n+ 1) rectangular box, thereby estab-
lishing the validity of the sum-of-squares formula.
Finally, each L-shaped region in a subdivided (1 + 2
+…+ n) ×(1 + 2 +…+ n) square has area given by a
cube number. Summing together these areas establishes
the sum-of-cubes formula.
A
RCHIMEDES OF
S
YRACUSE
(ca. 287–212
B
.
C
.
E
.)
knew the formula for the sum of the first ncounting
numbers. Arab scholars, who translated and pre-
served the works of Archimedes, were thus also
aware of the result. C
ARL
F
RIEDRICH
G
AUSS
(1777–1855) is said to have discovered the same for-
mula as a school student, employing a clever trick of
writing the same sum forward and backward. (This is
now considered a standard technique in the study of
ARITHMETIC SEQUENCES
.)
In 1713 Swiss mathematician Jacques Bernoulli of
the famous B
ERNOULLI FAMILY
searched for a general
formula for the sum of the first few kth powers: 1k+ 2k
+ 3k+…+ nk. He noticed that this sum appears as the
coefficient of xkin the T
AYLOR SERIES
of
k!(1 + ex+ e2x+…+ enx)
(To see this, write out each term emx as a series 1 + mx
+ +… Then add and collect all terms containing
the expression xk.) Using the formula for the
sum of a
GEOMETRIC SEQUENCE
, this expression can
be rewritten as:
The first factor here is k!, and the Taylor series of the
second factor is straightforward:
Unfortunately, the Taylor series of the third factor is
difficult to compute. Bernoulli decided to simply write:
for some numbers B0, B1, B2, … yet to be determined.
Given this, it now follows that 1k+ 2k+ 3k+…+ nkis
the coefficient of xkin the product:
Expanding brackets and identifying the coefficient of
xkin this product eventually leads to the remarkable
formula:
where a quantity Bris to be interpreted as the value Br.
The numbers B0, B1, B2, … are today known as the
Bernoulli numbers, and their values are given by:
with Bk= 0 for all odd values of kgreater than 1.
Thus, as an example, we again have:
The Bernoulli numbers have since been studied
extensively, and many of their properties are now well
understood. These numbers make an appearance in
evaluating the
ZETA FUNCTION
at even values. Specifi-
cally, mathematicians have shown that:
123 1
3
13131
3
13
211
21
3
12 1
6
222 2 33
3021233
32
++++=++
=++++++
=+− ++ +
=++
LnnBB
nBnBnBBB
nnn
nn n
()
() () ()
() () ()
()( )
BB B B B
01 2 4 6
11
2
1
6
1
30
1
42
== = = =,,, ,,K
123 1
1
11
kkk k kk
nnBB
k
++++=++
+
++
L()
kn n xnx
BBxB
xBx
!( ) ( ) !()
!
!!
+++ ++ +
⋅++ + +
11
213
23
23
2
01 2
2
3
3
L
L
x
eBBxB
xBx
x=+ + + +
123
01 2
2
3
3
!!
L
e
xnn
xnx
nx() ()()
!()
!
+=+++ ++ +
123
2
111
213L
ke
eke
x
x
e
xn
x
nx
x
!!
()
()
=⋅
++
11
1
1
1
1
mx
22
2!
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