
506 triangle
Turning a pencil inside a triangle
Establishing the converse of Pythagoras’s theorem
This demonstration shows that the net effect of
rotating a pencil through each of the three angles of a
triangle is to rotate the pencil through half a turn.
Thus the three angles of the triangle do indeed sum to
180°. Moreover, it is clear that this argument would
work for any triangle one could draw. A similar argu-
ment shows that the sum of angles in any quadrilat-
eral is 360° in any five-sided polygon, 540°, and, in
general, the sum of angles in any N-sided shape is
(N– 2) ×180°.
Triangles are classified according to the relative
lengths of their sides: A triangle is scalene if each side is
of a different length, isosceles if at least two sides are
equal in length, and equilateral if all three sides are the
same length. A study of the SAS principle shows that
the angles
OPPOSITE
the two sides equal in length in an
isosceles triangle have equal measure. As an equilateral
triangle is also isosceles, it follows that an equilateral
triangle is
EQUIANGULAR
, that is, all three angles have
the same measure (of 60°).
Triangles can alternatively be classified according to
their angles. An acute triangle has all three angles less
than 90°in measure, a right triangle contains precisely
one angle equal to 90°, and an obtuse triangle contains
one angle of measure greater than 90°. (It is not possi-
ble for a triangle to possess two obtuse angles.)
If a picture of a triangle is oriented so that one side
of the triangle is horizontal, then that side is called the
base of the triangle. The height of the triangle is the ver-
tical distance between the base of the figure and the ver-
tex of the triangle that does not lie on the base. A study
of
AREA
shows that, if oriented appropriately, the inte-
rior of a triangle occupies half the interior of the rectan-
gle that encloses the triangle, with the base as one side
of the rectangle. Thus the area of a triangle is given by
the formula:
If the three sides of the triangle are of lengths a, b, and
c, then H
ERON
’
S FORMULA
also shows that the area of
the triangle is given by:
where is the semiperimeter of the triangle.
P
YTHAGORAS
’
S THEOREM
shows that if a right tri-
angle has side-lengths a, b, and c, with the sides aand
bsurrounding the right angle, then a2+ b2= c2. The
TRIANGLE INEQUALITY
follows as a consequence.
For an arbitrary triangle with side-lengths a, b, and
c, if the angle between sides aand bis acute (that is, less
than 90°), then a2+ b2> c2. If, on the other hand, the
angle between sides aand bis obtuse (greater than 90°),
then a2+ b2< c2. This follows from the
LAW OF
COSINES
. It can also be seen algebraically as follows:
For the diagram below left, the angle between
sides aand bis acute. We clearly have a> xand
b> y, and so a2+ b2> x2+ y2= c2. For the dia-
gram below right, the angle between sides aand
bis obtuse. We clearly have x> a. Consequently:
c2= x2+ y2
= x2+ (b2– (x– a)2)
= b2+ 2ax – a2
< b2+ 2a· a– a2= b2+ a2
These observations provide a proof of the
CONVERSE
of
Pythagoras’s theorem:
If, for a triangle with side-lengths a, b, and c,
we have a2+ b2= c2, then the triangle is a right
triangle with right angle between the sides of
length aand b.
sabc
=++
2
area = −−−ss a s b s c()()()
area base height=× ×
1
2