a compact metric space is second countable
Proposition.
Every compact metric space is second countable.
Proof.
Let be a compact metric space, and for each define , where denotes the open ball centered about of http://planetmath.org/node/1296radius . Each such collection
![]()
is an open cover of the compact space , so for each there exists a finite collection that . Put . Being a countable
![]()
union of finite sets
![]()
, it follows that is countable; we assert that it forms a basis for the metric topology on . The first property of a basis is satisfied trivially, as each set is an open cover of . For the second property, let , , and suppose . Because the sets and are open in the metric topology on , their intersection
![]()
is also open, so there exists such that . Select such that . There must exist such that (since is an open cover of ). To see that , let . Then we have
| (1) |
so that , from which it follows that , hence that . Thus the countable collection forms a basis for a topology![]()
on ; the verification that the topology by is in fact the metric topology follows by an to that used to verify the second property of a basis, and completes
the proof that is second countable.∎
It is worth nothing that, because a countable union of countable sets is countable, it would have been sufficient to assume that was a Lindelöf space.
| Title | a compact metric space is second countable |
| Canonical name | ACompactMetricSpaceIsSecondCountable |
| Date of creation | 2013-03-22 17:00:49 |
| Last modified on | 2013-03-22 17:00:49 |
| Owner | azdbacks4234 (14155) |
| Last modified by | azdbacks4234 (14155) |
| Numerical id | 17 |
| Author | azdbacks4234 (14155) |
| Entry type | Theorem |
| Classification | msc 54D70 |
| Related topic | MetricSpace |
| Related topic | Compact |
| Related topic | Lindelof |
| Related topic | Ball |
| Related topic | basisTopologicalSpace |
| Related topic | Cover |
| Related topic | BasisTopologicalSpace |