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单词 IfAIsInfiniteAndBIsAFiniteSubsetOfAThenAsetminusBIsInfinite
释义

if A is infinite and B is a finite subset of A\\tmspace+.1667em\\tmspace-.1667em, then AB is infinite


Theorem. If A is an infinite setMathworldPlanetmath and B is afinite subset of A, then AB is infinite.

Proof. The proof is by contradictionMathworldPlanetmathPlanetmath. If ABwould be finite, there would exist a k and a bijectionf:{1,,k}AB. Since B is finite, therealso exists a bijection g:{1,,l}B. We can then definea mapping h:{1,,k+l}A by

h(i)={f(i)wheni{1,,k},g(i-k)wheni{k+1,,k+l}.

Since f and g are bijections, h is a bijection betweena finite subset of and A. This is a contradictionsince A is infinite.

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更新时间:2025/5/5 3:48:44