monotonicity of the sequence
Theorem 1.
Let be a real number and let be an integer such that and . Then
Proof.
We begin by dividing the two expressions to be compared:
Now, when , we have
whilst, when and , we have,
Therefore, we may apply an inequality for differences of powers to conclude
Hence, we have
Note that the numerator is greater than the denominator becauseit contains every term contained in the denominator and an extraterm . Hence this ratio is larger than ; multiplying out,we obtain the inequality which was to be demonstrated.∎