open set

In a metric space $M$ a set $O$ is called an open subset of $M$ or just open, if for every $x\in O$ there is an open ball $S$ around $x$ such that $S\subset O$. If $d(x,y)$ is the distance from $x$ to $y$ then the open ball $B_r$ with radius $r>0$ around $x$ is given as:

Using the idea of an open ball one can define a neighborhood of a point $x$. A set containing $x$ is called a neighborhood of $x$ if there is an open ball around $x$ which is a subset of the neighborhood.

These neighborhoods have some properties, which can be used to define a topological space using the Hausdorff axioms for neighborhoods, by which again an open set within a topological space can be defined. In this way we drop the metric and get the more general topological space. We can define a topological space $X$ with a set of neighborhoods of $x$ called $U_x$ for every $x\in X$, which satisfy

1. $x\in U$ for every $U\in U_x$

2. If $U\in U_x$ and $V\subset X$ and $U\subset V$ then $V\in U_x$ (every set containing a neighborhood of $x$ is a neighborhood of $x$ itself).

3. If $U,V\in U_x$ then $U\cap V\in U_x$.

4. For every $U\in U_x$ there is a $V\in U_x$, such that $V\subset U$ and $V\in U_p$ for every $p\in V$.

The last point leads us back to open sets, indeed a set $O$ is called open if it is a neighborhood of every of its points. Using the properties of these open sets we arrive at the usual definition of a topological space using open sets, which is equivalent to the above definition. In this definition we look at a set $X$ and a set of subsets of $X$, which we call open sets, called $𝒪$, having the following properties:

1. $\mathrm{\varnothing }\in 𝒪$ and $X\in 𝒪$.

2. Any union of open sets is open.

3. intersections of open sets are open.

Note that a topological space is more general than a metric space, i.e. on every metric space a topology can be defined using the open sets from the metric, yet we cannot always define a metric on a topological space such that all open sets remain open.

Examples:

• On the real axis the interval $I=(0,1)$ is open because for every $a\in I$ the open ball with radius $\min (a,1-a)$ is always a subset of $I$. (Using the standard metric $d(x,y)=|x-y|$.)

• The open ball $B_r$ around $x$ is open. Indeed, for every $y\in B_r$ the open ball with radius $r-d(x,y)$ around y is a subset of $B_r$, because for every $z$ within this ball we have:

  So and thus $z$ is in $B_r$. This holds for every $z$ in the ball around $y$ and therefore it is a subset of $B_r$

• A non-metric topology would be the finite complement topology on infinite sets, in which a set is called open, if its complement is finite.