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单词 ProofOfBondyAndChvatalTheorem
释义

proof of Bondy and Chvátal theorem


Proof.

The sufficiency of the condition is obvious and we shall prove the necessity bycontradictionMathworldPlanetmathPlanetmath.

Assume that G+uv is Hamiltonian but G is not.Then G+uv has a Hamiltonian cycleMathworldPlanetmath containing the edge uv. Thus there exists a path P=(x1,,xn) in G from x1=u to xn=v meeting all the vertices of G. If xi is adjacent to x1 (2in) then xi-1 is not adjacent to xn, for otherwise(x1,xi,xi+1,,xn,xi-1,xi-2,,x1) is a Hamiltonian cycle of G. Thus d(xn)(n-1)-d(x1), that is d(u)+d(v)n-1, a contradiction∎

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