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单词 ProofOfCrossingLemma
释义

proof of crossing lemma


Euler’s formula implies the linear lower bound cr(G)m-3n+6, and so it cannot be used directly. What we need is to consider the subgraphsMathworldPlanetmath of our graph, apply Euler’s formula on them, and then combine the estimates. The probabilistic method provides a natural way to do that.

Consider a minimal embedding of G. Choose independently every vertex of G with probability p. Let Gp be a graph induced by those vertices. By Euler’s formula, cr(Gp)-mp+3np0. The expectation is clearly

E(cr(Gp)-mp+3np)0.

Since E(np)=pn, E(mp)=p2m and E(Xp)=p4cr(G), we get an inequality that bounds the crossing number of G from below,

cr(G)p-2m-3p-3n.

Now set p=4nm (which is at most 1 since m4n), and the inequaliy becomes

cr(G)164m3n2.

Similarly, if m92n, then we can set p=9n2m to get

cr(G)4243m3n2.

References

  • 1 Martin Aigner and Günter M. Ziegler. Proofs from THE BOOK. Springer, 1999.
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