“ProofOfNakayamasLemma”的概念、定义、习题解题方法及翻译-数学辞典

单词	ProofOfNakayamasLemma
释义	proof of Nakayama’s lemma (This proof was taken from [1].) If $M$ were not zero, it would have a simple quotient, isomorphic to $R/\\mathfrak{m}$ for some maximal ideal $\\mathfrak{m}$ of $R$ . Then we would have $\\mathfrak{m}M\eq M$ , so that $\\mathfrak{a}M\eq M$ as $\\mathfrak{a}\\subseteq\\mathfrak{m}$ . References 1 Serre, J.-P. Local Algebra. Springer-Verlag, 2000.
随便看	geometric mean GeometricRandomVariable geometric random variable GeometricRepresentationOfRelationComposition geometric representation of relation composition GeometricSequence geometric sequence GeometricSeries geometric series GeometrizationOfmathbbRn geometrization of ℝ^n Geometry geometry GeometryAsTheStudyOfInvariantsUnderCertainTransformations geometry as the study of invariants under certain transformations GeorgeDantzig George Dantzig GeorgePolya George Pólya GeorgFrobenius Georg Frobenius GergonnePoint Gergonne point GergonneTriangle Gergonne triangle

数学辞典收录了18232条数学词条，基本涵盖了常用数学知识及数学英语单词词组的翻译及用法，是数学学习的有利工具。

proof of Nakayama’s lemma