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单词 ProofOfPoincareRecurrenceTheorem1
释义

proof of Poincaré recurrence theorem 1


Let An=k=nf-kE. Clearly, EA0 andAiAj when ji. Also, Ai=fj-iAj, so that μ(Ai)=μ(Aj) for all i,j0, bythe f-invariance of μ.Now for any n>0 we have E-AnA0-An, so that

μ(E-An)μ(A0-An)=μ(A0)-μ(An)=0.

Hence μ(E-An)=0 for all n>0, so thatμ(E-n=1An)=μ(n=1E-An)=0.But E-n=1An is precisely the set of those xE suchthat for some n and for all k>n we have fk(x)E.

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