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单词 ProofOfTheBurnsideBasisTheorem
释义

proof of the Burnside basis theorem


Let P be a p-group and Φ(P) its Frattini subgroupMathworldPlanetmath.

Every maximal subgroup Q of P is of index p in P and is thereforenormal in P. Thus P/Qp. So givengP, gpQwhich proves PpQ. Likewise, p is abelianMathworldPlanetmath so[P,P]Q. As Q is any maximal subgroup, it follows [P,P] andPp lie in Φ(P).

Now both [P,P] and Pp are characteristic subgroups of P so in particularF=[P,P]Pp is normal in P. If we pass to V=P/F we find that V is abelian and every element has order p – that is, V is a vector spaceMathworldPlanetmath over p. So the maximal subgroups of P are in a 1-1 correspondence with the hyperplanesMathworldPlanetmathPlanetmath of V. As the intersectionMathworldPlanetmath of all hyperplanes of a vector space is the origin, it follows the intersection of all maximal subgroups of P is F. That is, [P,P]Pp=Φ(P).

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