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单词 ProofOfTheDebutTheorem
释义

proof of the début theorem


Let ()t𝕋 be a right-continuous filtration (http://planetmath.org/FiltrationOfSigmaAlgebras) on the measurable spaceMathworldPlanetmathPlanetmath (Ω,), It is assumed that 𝕋 is a closed subset of and that t is universally complete for each t𝕋.

If A𝕋×Ω is a progressively measurable set, then we show that its début

D(A)=inf{t𝕋:(t,ω)A}

is a stopping time.

As A is progressively measurable, the set A((-,t)×Ω) is (𝕋)×t-measurable. By the measurable projection theorem it follows that

{D(A)<t}={ωΩ:(s,ω)A((-,t)×Ω) for some s𝕋}

is in t. If there exists a sequence tn𝕋 with tn>t and tnt, then

{D(A)t}=n{D(A)<tn}ntn=t+=t.

On the other hand, if t is not a right limit point of 𝕋 then

{D(A)t}={D(A)<t}{ωΩ:(t,ω)A}t.

In either case, {D(A)t} is in t, so D(A) is a stopping time.

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更新时间:2025/5/4 6:44:19