sines law

Sines Law.
Let $A B C$ be a triangle where $a, b, c$ are the sides opposite to $A, B, C$ respectively, and let $R$ be the radius of the circumcircle. Then the following relation holds:

\\frac{a}{\\sin A}=\\frac{b}{\\sin B}=\\frac{c}{\\sin C}=2R.

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