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单词 1122DedekindRealsAreCauchyComplete
释义

11.2.2 Dedekind reals are Cauchy complete


Recall that x: is a Cauchy sequenceMathworldPlanetmathPlanetmath when it satisfies

(ϵ:+)(n:)(m,kn)|xm-xk|<ϵ.(11.2.1)

Note that we did not truncate the inner existential because we actually want tocompute rates of convergence—an approximation without an error estimate carries littleuseful information. By \\autorefthm:ttac, (11.2.1) yields a function M:+, called the modulus of convergence, such that m,kM(ϵ)implies |xm-xk|<ϵ. From this we get |xM(δ/2)-xM(ϵ/2)|<δ+ϵ for all ϵ:+. In fact, the map (ϵxM(ϵ/2)):+ carries the same information about the limit as theoriginal Cauchy condition (11.2.1). We shall work with theseapproximation functions rather than with Cauchy sequences.

Definition 11.2.2.

A Cauchy approximationis a map x:Q+Rd which satisfies

(δ,ϵ:+).|xδ-xϵ|<δ+ϵ.(11.2.2)

The limitof a Cauchy approximation x:Q+Rd is a number :Rd suchthat

(ϵ,θ:+).|xϵ-|<ϵ+θ.
Theorem 11.2.4.

Every Cauchy approximation in Rd has a limit.

Proof.

Note that we are showing existence, not mere existence, of the limit.Given a Cauchy approximation x:+𝖽, define

Ly(q):(ϵ,θ:+).Lxϵ(q+ϵ+θ),
Uy(q):(ϵ,θ:+).Uxϵ(q-ϵ-θ).

It is clear that Ly and Uy are inhabited, rounded, and disjoint. To establishlocatedness, consider any q,r: such that q<r. There is ϵ:+ suchthat 5ϵ<r-q. Since q+2ϵ<r-2ϵ merelyLxϵ(q+2ϵ) or Uxϵ(r-2ϵ). In the first casewe have Ly(q) and in the second Uy(r).

To show that y is the limit of x, consider any ϵ,θ:+. Because is dense in 𝖽 there merely exist q,r: such that

xϵ-ϵ-θ/2<q<xϵ-ϵ-θ/4<xϵ<xϵ+ϵ+θ/4<r<xϵ+ϵ+θ/2,

and thus q<y<r. Now either y<xϵ+θ/2 or xϵ-θ/2<y.In the first case we have

xϵ-ϵ-θ/2<q<y<xϵ+θ/2,

and in the second

xϵ-θ/2<y<r<xϵ+ϵ+θ/2.

In either case it follows that |y-xϵ|<ϵ+θ.∎

For sake of completeness we record the classic formulation as well.

Corollary 11.2.5.

Suppose x:NRd satisfies the Cauchy condition (11.2.1). Thenthere exists y:Rd such that

(ϵ:+)(n:)(mn)|xm-y|<ϵ.
Proof.

By \\autorefthm:ttac there is M:+ such that x¯(ϵ):xM(ϵ/2) is a Cauchy approximation. Let y be its limit, which exists by\\autorefRD-cauchy-complete. Given any ϵ:+, let n:M(ϵ/4)and observe that, for any mn,

|xm-y||xm-xn|+|xn-y|=|xm-xn|+|x¯(ϵ/2)-y|<ϵ/4+ϵ/2+ϵ/4=ϵ.
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