complementary subspace
Direct sum decomposition.
Let be a vector space, and subspaces
. We say that and span , and write
ifevery can be expressed as a sum
for some and .
If in addition, such a decomposition is unique for all , orequivalently if
then we say that and form a direct sum decomposition of and write
In such circumstances, we also say that and are complementary subspaces, and also say that is an algebraic complement of .
Here is useful characterization of complementary subspaces if isfinite-dimensional.
Proposition 1
Let be as above, and suppose that isfinite-dimensional. The subspaces and are complementary ifand only if for every basis of andevery basis of , the combined list
is a basis of .
Remarks.
- •
Since every linearly independent subset of a vector space can be extended to a basis, every subspace has a complement
, and the complement is necessarily unique.
- •
Also, direct sum decompositions of a vector space are in a one-to correspondence fashion with projections on .
Orthogonal decomposition.
Specializing somewhat, suppose that the ground field is eitherthe real or complex numbers, and that is either an inner productspace or a unitary space, i.e. comes equipped with apositive-definite inner product
In such circumstances,for every subspace we define the orthogonal complement of, denoted by to be the subspace
Proposition 2
Suppose that is finite-dimensional and a subspace.Then, and its orthogonalcomplement determine a direct sum decomposition of .
Note: the Proposition is false if either the finite-dimensionalityor the positive-definiteness assumptions
are violated.