Galois groups of finite abelian extensions of
Theorem.
Let be a finite abelian group with . Then there exist infinitely many number fields with Galois and .
Proof.
This will first be proven for cyclic.
Let . By Dirichlet’s theorem on primes in arithmetic progressions, there exists a prime with . Let denote a root of unity. Let . Then is Galois with cyclic of order (http://planetmath.org/OrderGroup) . Since divides , there exists a subgroup
of such that . Since is cyclic, it is abelian
, and is a normal subgroup
of . Let , the subfield
of fixed (http://planetmath.org/FixedField) by . Then is Galois with cyclic of order . Thus, .
Let and be distinct primes with and . Then there exist subfields and of and , respectively, such that and . Note that since . Thus, . Therefore, for every prime with , there exists a distinct number field such that is Galois and . The theorem in the cyclic case follows from using the full of Dirichlet’s theorem on primes in arithmetic progressions: There exist infinitely many primes with .
The general case follows immediately from the above , the fundamental theorem of finite abelian groups (http://planetmath.org/FundamentalTheoremOfFinitelyGeneratedAbelianGroups), and a theorem regarding the Galois group of the compositum of two Galois extensions
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