generalized Riemann-Lebesgue lemma
Generalized Riemann-Lebesgue lemmaFernando Sanz Gamiz
Lemma 1.
Let be a bounded measurable function.If satisfies the averaging condition
then
with for any
Proof.
Obviously we only need to prove the lemma when both and arereal and .
Let be the indicator function of theinterval . Then
by the hypothesis. Hence, the lemma is valid for indicators,therefore for step functions
.
Now let be a bound for and choose .As step functions are dense in , we can find, for any , a step function such that ,therefore
because by what we have proved for stepfunctions. Since is arbitrary, we are done.
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