measurable projection theorem
The projection of a measurable set![]()
from the product
of two measurable spaces
![]()
need not itself be measurable. See a Lebesgue measurable but non-Borel set for an example. However, the following result can be shown. The notation refers to the product -algebra (http://planetmath.org/ProductSigmaAlgebra).
Theorem.
Let be a measurable space and be a Polish space![]()
with Borel -algebra .Then the projection (http://planetmath.org/ProjectionMap) of any onto is universally measurable.
In particular, if is universally complete then the projection of will be in , and this applies to all complete -finite (http://planetmath.org/SigmaFinite) measure spaces
![]()
. For example, the projection of any Borel set in onto is Lebesgue measurable.
The theorem is a direct consequence of the properties of analytic sets![]()
(http://planetmath.org/AnalyticSet2), following from the result that projections of analytic sets are analytic and the fact that analytic sets are universally measurable (http://planetmath.org/MeasurabilityOfAnalyticSets).Note, however, that the theorem itself does not refer at all to the concept of analytic sets.
The measurable projection theorem has important applications to the theory of continuous-time stochastic processes. For example, the début theorem, which says that the first time at which a progressively measurable stochastic process![]()
enters a given measurable set is a stopping time, follows easily.Also, if is a jointly measurable process defined on a measurable space , then the maximum process will be universally measurable since,
is universally measurable, where is the projection map.Furthermore, this also shows that the topology![]()
of ucp convergence is well defined on the space of jointly measurable processes.