请输入您要查询的字词:

 

单词 ProofOfProductRule
释义

proof of product rule


We begin with two differentiable functions f(x) and g(x) and show that their product is differentiableMathworldPlanetmath, and that the derivative of the product has the desired form.

By simply calculating, we have for all values of x in the domain of f and g that

ddx[f(x)g(x)]=limh0f(x+h)g(x+h)-f(x)g(x)h
=limh0f(x+h)g(x+h)+f(x+h)g(x)-f(x+h)g(x)-f(x)g(x)h
=limh0[f(x+h)g(x+h)-g(x)h+g(x)f(x+h)-f(x)h]
=limh0[f(x+h)g(x+h)-g(x)h]+limh0[g(x)f(x+h)-f(x)h]
=f(x)g(x)+f(x)g(x).

The key argument here is the next to last line, where we have used the fact that both f and g are differentiable, hence the limit can be distributed across the sum to give the desired equality.

随便看

 

数学辞典收录了18232条数学词条,基本涵盖了常用数学知识及数学英语单词词组的翻译及用法,是数学学习的有利工具。

 

Copyright © 2000-2023 Newdu.com.com All Rights Reserved
更新时间:2025/5/4 9:15:30