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单词 ProofOfStirlingsApproximation
释义

proof of Stirling’s approximation


Computing the Taylor expansionMathworldPlanetmath with remainder of thefunctions log and xxlogx-x, we have

(n+1)log(n+1)-log(n+1)=nlogn-n+logn+12n+16ξn2
log(n+1)=logn+1n-12ηn2

where nξnn+1 and nηnn+1.Summing the first equation from 1 to n-1, we have

nlogn-n=-1+log(n-1)!+12m=1n-11m+16m=1n-11ξn2.
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更新时间:2025/5/4 5:05:16