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单词 RigorousDefinitionOfTrigonometricFunctions
释义

rigorous definition of trigonometric functions


It is possible to define the trigonometric functionsDlmfMathworldPlanetmath rigorously by means of aprocess based upon the angle addition identities. A sketch of how this is doneis provided below.

To begin, define a sequenceMathworldPlanetmath {cn}n=1 by the initial conditionMathworldPlanetmathc1=1 and the recursion

cn+1=1-1-cn2.

Likewise define a sequence {sn}n=1 by the conditions s1=1 and

sn+1=cn2.

(In both equations above, we take the positive square rootMathworldPlanetmath.)It may be shown that both of these sequences are strictly decreasingPlanetmathPlanetmath and approach 0.

Next, define a sequence of 2×2 matrices as follows:

mn=(1-cnsn-sn1-cn)

Using the recursion relations which define cn and sn, it may be shown thatmn+12=mn, More grenerally, using induction, this can be generalised tomn+k2k=mn.

It is easy to check that the product of any two matrices of the form

(xy-yx)

is of the same form. Hence, for any integers k and n, the matrixmnk will be of this form. We can therefore define functionsMathworldPlanetmath S andC from rational numbers whose denominator is a power of two to realnumbers by the following equation:

(C(n2k)S(n2k)-S(n2k)C(n2k))=(1-cksk-sk1-ck)n.

From the recursion relations, we may prove the following identities:

S2(r)+C2(r)=1
S(p+q)=S(p)C(q)+S(q)C(p)
C(p+q)=C(p)C(q)-S(p)S(q)

From the fact that cn0 and sn0 as n, itfollows that, if {pn}n=1 and {qn}n=1 aretwo sequences of rational numbers whose denominators are powers of twosuch that limnpn=limnqn, thenlimnC(pn)=limnC(qn) andlimnS(pn)=limnS(qn). Therefore,we may define functions by the conditions that, for any convergentseriesMathworldPlanetmathPlanetmath of rational numbers {rn}n=0 whose denominatorsare powers of two,

cos(πlimnrn)=limnC(rn)

and

sin(πlimnrn)=limnS(rn).

By continuity, we see that these functions satisfy the angle additionidentities.

Application. Let us use the definitions above to find sin(π2) and cos(π2). Let ri:=12 for every positive integer i. Then we need to find C(12) and S(12). We use the matrix above defining C and S, and set n=k=1:

(C(12)S(12)-S(12)C(12))=(1-c1s1-s11-c1)=(01-10).

As a result, cos(π2)=cos(πlimi12)=limiC(12)=C(12)=0. Similarly, sin(π2)=1.

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更新时间:2025/5/4 6:39:16