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单词 SheafOfSections
释义

sheaf of sections


0.1 Presheaf Definition

Consider a rank r vector bundleMathworldPlanetmath EM, whose typical fibre is defined with respect to a field k. Let {Uα} constitute a coverfor M. Then, sectionsPlanetmathPlanetmathPlanetmath of the bundle over some UM are definedas continuous functions UE, which commute with the natural projectionMathworldPlanetmathmap π:EM; πs=idM. Denote the space of sections ofthe bundle over U to be Γ(U,E). The space of sections is a vectorspaceMathworldPlanetmath over the field k by defining addition and scalar multiplication pointwise: for s,tΓ(U,E), pU and ak

(s+t)(p)s(p)+t(p)    (as)(p)as(p).

Then, this forms a presheaf , a functor from ((topM))to the category of vector spaces, with restrictionPlanetmathPlanetmathPlanetmath maps the naturalrestriction of functions.

0.2 Sheaf Axioms

It is easy to see that it satisfies the sheafaxioms: for U open and {Vi} a cover of U,

  1. 1.

    if s(U) and s|Vi=0 for all i, then s=0.

  2. 2.

    if si(Vi) for all i, such that for each i,j withViVj, si|ViVj=sj|ViVj, then there is an s(U) with s|Vi=si forall i.

The first follows from the fact that for any U, there is always at leastone element of (U), the zero section, and that the transitionfunctionsMathworldPlanetmath of the bundle are linear maps. The second follows by the construction of the bundle.

1 Sheafification

We may also see the vector bundle by applying associated sheaf constructionto the presheaf UΓ(U,E). First though, we show that thestalk of the sheaf at a point is isomorphicPlanetmathPlanetmathPlanetmath to the fibre of thebundle E at the point. Let [s,U] be a germ at pM (pUM), and define a map ψ:pEp by

ψ:[s,U]sp.

First, we show that the map is a vector space homomorphism. Consider twogerms [s,U] and [t,V] in p. These map to sp and tprespectively. We add the germs by finding an open set WUV andadding the restrictions of the sections;

[s,U]+[t,V][s|W+t|W,W].

Of course, pW, so we have ψ(s|W+t|W)=sp+tp, since therestriction maps are simply restriction of functions.Now, it is easy to show that ψ is injectivePlanetmathPlanetmath.Assume ψ([t,V])=ψ([s,U])=sp. Then

ψ([t,V])-ψ([s,U])=sp-sp
ψ([t,V]-[s,U])=0
=[s,U]

Now, we show that ψ is surjectivePlanetmathPlanetmath. For spEp, let UMopen be isomorphic to some subset U of m. Then, Γ(U,E) is theset of continuous maps UVE, where VE is the typical fibre of E;

Γ(U,E)=i=1r𝒞U.

Then let [s,U] be the constant function s:Usx, and wehave constructed an isomorphismPlanetmathPlanetmathPlanetmathPlanetmathPlanetmath ψ between p and Ep.

To construct the Étalé space, take the disjoint unionMathworldPlanetmath of stalks,Spé()=pMp, and endow it withthe following topology: the open sets shall be of the form

Us={sp|sΓ(U,),pUM},

collectionMathworldPlanetmath of germs of sections at points in UM.

Then, the associated sheaf to is the presheaf which assignscontinuous maps Γ(U,Spé()) to each open U. These aremaps where the preimageMathworldPlanetmath of Us is open. Clearly, this implies thatΓ(U,E)Γ(U,Spé()). To go the other way, notethat open sets of Spé() are the images of continuous maps UE. An open subset of Spé() may be written as a union of Ut;Uts{tp,sp|pU}. Then, by single-valuedness of maps,a continuous map USpé() must map to Ut for some tΓ(U,E), so we have Γ(U,E)Γ(U,Spé()).

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更新时间:2025/5/4 4:06:08