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单词 ApplicationsOfSecondOrderRecurrenceRelationFormula
释义

applications of second order recurrence relation formula


We give two applications of the formula for sequences satisfying second order recurrence relations:

  1. 1.

    Recall that the Fibonacci sequenceMathworldPlanetmath satisfies the recurrence relation

    fn+1=fn+fn-1.

    Thus, f0=1, A=1, and B=1. Therefore, the theorem yields the following formulaMathworldPlanetmathPlanetmath for the Fibonacci sequence:

    fn=k=0n2(n-kk)
  2. 2.

    Fix (http://planetmath.org/Fix2) a prime p and define a sequenceMathworldPlanetmath s by sn=τ(pn), where τ denotes the Ramanujan tau functionDlmfPlanetmath. Recall that τ satisfies

    τ(pn+1)=τ(p)τ(pn)-p11τ(pn-1).

    Thus, s0=1, A=τ(p), and B=-p11. Therefore, the theorem yields

    τ(pn)=k=0n2(n-kk)(-p11)k(τ(p))n-2k.

    This formula is valid for all primes p and all nonnegative integers n.

Titleapplications of second order recurrence relation formula
Canonical nameApplicationsOfSecondOrderRecurrenceRelationFormula
Date of creation2013-03-22 17:51:46
Last modified on2013-03-22 17:51:46
OwnerWkbj79 (1863)
Last modified byWkbj79 (1863)
Numerical id8
AuthorWkbj79 (1863)
Entry typeApplication
Classificationmsc 11A25
Classificationmsc 11F11
Classificationmsc 11B39
Classificationmsc 11B37
Classificationmsc 03D20
Related topicFibonacciSequence
Related topicRamanujanTauFunction
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