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单词 CharacterizationOfTightFramesInmathbbRn
释义

characterization of tight frames in n


Question 1.

What conditions must the vectors {xi}i=1kRn satisfy in order to be a tight frame in Rn?

Solution.

Let E be the k×n matrix whose rows are the vectors {xi}i=1k:

E=(xi,1xi,nxk,1xk,n).

Then the tight frame condition i=1k|x,xi|2=Ax2 gives (Ex)TEx=AxTx for all xn, or ETE=AIn:

ETE=(i=1kxi,1xi,1i=1kxi,1xi,ki=1kxi,kxi,1i=1kxi,kxi,k)=(A0000A)=AIn.

Therefore, the vectors

{xi=(xi,1xi,n)}i=1kn

are an A-tight frame iff the vectors

{xi=(x1,ixk,i)}i=1nk,

i.e., the columns of E, are all of norm A and form an orthogonalMathworldPlanetmathPlanetmath family.

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更新时间:2025/5/4 21:35:10