coboundary definition of exterior derivative
Let be a smooth manifold, and
- •
let denote the algebra
of smooth functions
on ;
- •
let denote the Lie-algebra of smooth vector fields;
- •
and let denote the vector space
of smooth,differential
-forms.
Recall that a differential form is amultilinear, alternating
mapping
such that, in local coordinates, looks like a multilinear combination of its vector fieldarguments. Thus, employing the Einstein summation convention and localcoordinates , we have
where is a list of vector fields. Recall alsothat is a module. The action is given bya directional derivative, and takes the form
With these preliminaries out of the way, we have the followingdescription of the exterior derivative operator . For , we have
(1) | ||||
where indicates the omission of the argument .
The above expression (1) of can be taken asthe definition of the exterior derivative. Letting the arguments be coordinate vector fields, it is not hard to show that the above definition is equivalent to theusual definition of as a derivation of the exterior algebra ofdifferential forms, or the local coordinate definition of . Thenice feature of (1) is that it is equivalent to thedefinition of the coboundary operator for Lie algebra cohomology.Thus, we see that de Rham cohomology, which is the cohomology of thecochain complex
, is justzeroth-order Lie algebra cohomology of with coefficients in. The bit about “zeroth order” means that we areconsidering cochains that are zeroth order differential operators
oftheir arguments — in other words, differential forms.