Dedekind-finite
A ring is Dedekind-finite if for , whenever implies .
Of course, every commutative ring is Dedekind-finite. Therefore, the theory of Dedekind finiteness is trivial in this case. Some other examples are
- 1.
any ring of endomorphisms over a finite dimensional vector space (over a field)
- 2.
any division ring
- 3.
any ring of matrices over a division ring
- 4.
finite direct product
of Dedekind-finite rings
- 5.
by the last three examples, any semi-simple ring is Dedekind-finite.
- 6.
any ring with the property that there is a natural number
such that for every nilpotent element
The finite dimensionality in the first example can not be extended to the infinite case. Lam in [1] gave an example of a ring that is not Dedekind-finite arising out of the ring of endomorphisms over an infinite dimensional vector space (over a field).
References
- 1 T. Y. Lam, A First Course in Noncommutative Rings, Springer-Verlag, New York (1991).
- 2 T. Y. Lam, Lectures on Modules and Rings, Springer-Verlag, New York (1999).