concavity of sine function
Theorem 1.
The sine function is concave on the interval .
Proof.
Suppose that and lie in the interval .Then , , , and are allnon-negative. Subtracting the identities
and
from each other, we conclude that
This implies that if and only if, which is equivalent to statingthat if and only if . Taking square roots, we conclude that if and only if.
Hence, we have
Multiply out both sides and move terms to conclude
Applying the angle addition and double-angle identities for thesine function, this becomes
This is equivalent to stating that, for all,
which implies that is concave in the interval .∎