converse to Taylor’s theorem
Let be an open set.
Theorem.
Let be a function such that there exists a constant and an integer such that for each there is a polynomial of where
for near 0. Then ( is continuously differentiable) and the Taylor expansion (http://planetmath.org/TaylorSeries) of of about any is given by .
Note that when the hypothesis of the theorem is just that is Lipschitz in which certainly makes it continuous
in .
References
- 1 Steven G. Krantz, Harold R. Parks..Birkhäuser, Boston, 2002.