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单词 DualOfDilworthsTheorem
释义

dual of Dilworth’s theorem


Theorem 1.

Let P be a poset of height h. Then P can be partitioned into h antichainsMathworldPlanetmath and furthermore at least h antichains are required.

Proof.

InductionMathworldPlanetmath on h. If h=1, then no elements of P are comparablePlanetmathPlanetmath, so P is an antichain. Now suppose that P has height h2 and that the theorem is true for h-1. Let A1 be the set of maximal elementsMathworldPlanetmath of P. Then A1 is an antichain in P and P-A1 has height h-1 since we have removed precisely one element from every chain. Hence, P-A1 can be paritioned into h-1 antichains A2,A3,Ah. Now we have the partitionMathworldPlanetmathPlanetmath A1A2Ah of P into h antichains as desired.

The necessity of h antichains is trivial by the pigeonhole principleMathworldPlanetmath; since P has height h, it has a chain of length h, and each element of this chain must be placed in a different antichain of our partition.∎

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