example of transcendental number
The following is a classical application of Liouville’s approximation theorem. For completeness, we state Liouville’s result here:
Theorem 1.
For any algebraic number with degree , there exists a constant such that:
for all rationals (with ).
Next we use the theorem to construct a transcendental number.
Corollary 1.
The real number
is transcendental.
Proof.
Clearly, the number is well defined, i.e. the series converges. Indeed,
and . Thus, by the comparison test, the series converges and .
Suppose, for a contradiction, that is algebraic of degree . We will construct infinitely many rationals such that
where is the constant given by the theorem above. Let be such that . Then, in fact, we will show that there are infinitely many rationals with such that
For all we define a rational number by:
then and are relatively prime integers and we have:
where in the last inequality we have used the fact that . Therefore, all rationals satisfy the desired inequality, which leads to the contradiction with the theorem above. Thus cannot be algebraic and it must be transcendental.∎
Many other similar transcendental numbers can be constructed in this fashion.