all orthonormal bases have the same cardinality
Theorem. – All orthonormal bases of an Hilbert space
have the same cardinality. It follows that the concept of dimension
of a Hilbert space is well-defined.
Proof: When is finite-dimensional (as a vector space), every orthonormal basis is a Hamel basis
of . Thus, the result follows from the fact that all Hamel bases of a vector space have the same cardinality (see this entry (http://planetmath.org/AllBasesForAVectorSpaceHaveTheSameCardinality)).
We now consider the case where is infinite-dimensional (as a vector space). Let and be two orthonormal basis of , indexed by the sets and , respectively. Since is infinite dimensional the sets and must be infinite.
We know, from Parseval’s equality, that for every
We know that, in the above sum, for only a countable number of . Thus, considering as , the set is countable. Since for each we also have
there must be such that . We conclude that .
Hence, since each is countable, (because is infinite).
An analogous proves that . Hence, by the Schroeder-Bernstein theorem and have the same cardinality.