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单词 ProofOfTrigonometricVersionOfCevasTheorem
释义

proof of trigonometric version of Ceva’s theorem


The proof goes by proving the condition imposed on the sines, is equivalentMathworldPlanetmathPlanetmathPlanetmathPlanetmathPlanetmath to the one imposed on the sides on the normal version of Ceva’s theorem.

We want to prove

sinACZsinZCBsinBAXsinXACsinCBYsinYBA=1

if and only if

AZZBBXXCCYYA=1.

Now, the generalization of bisectors theorem states that

AZZB=CAsinACZBCsinZCB,
BXXC=ABsinBAXCAsinXAC,
CYYA=BCsinCBYABsinYBA.

Multiplying the three equations, and cancelling all segments on the right side gives the desired equivalence.

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更新时间:2025/5/4 5:52:54