Sobolev inequality
For , define the Sobolev conjugate of as
Note that .
In the following statement represent the weak derivative and is the Sobolev space![]()
of functions whose weak derivative is itself in .
Theorem 1
Assume that and let be a bounded, open subset of with Lipschitz
boundary.Then there is a constant such that, for all one has
We can restate the previous Theorem by saying that the Sobolev space is a subspace![]()
of the Lebesgue space and that the inclusion map
![]()
is continuous
![]()
.
| Title | Sobolev inequality |
| Canonical name | SobolevInequality |
| Date of creation | 2013-03-22 15:05:14 |
| Last modified on | 2013-03-22 15:05:14 |
| Owner | paolini (1187) |
| Last modified by | paolini (1187) |
| Numerical id | 10 |
| Author | paolini (1187) |
| Entry type | Theorem |
| Classification | msc 46E35 |
| Synonym | Sobolev embedding |
| Synonym | sobolev immersion |
| Synonym | Gagliardo Nirenberg inequality |
| Related topic | LpSpace |
| Defines | Sobolev conjugate |
| Defines | Sobolev exponent |